贪吃蛇是一种经典的游戏，可以通过编程实现。以下是一个简单版本的贪吃蛇游戏的编程示例，以及游戏的玩法说明。

Python代码示例：

```python

import pygame

import time

import random

pygame.init()

white = (255, 255, 255)

yellow = (255, 255, 102)

black = (0, 0, 0)

red = (213, 50, 80)

green = (0, 255, 0)

blue = (50, 153, 213)

dis_width = 800

dis_height = 600

dis = pygame.display.set_mode((dis_width, dis_height))

pygame.display.set_caption('贪吃蛇游戏')

clock = pygame.time.Clock()

snake_block = 10

snake_speed = 30

font_style = pygame.font.SysFont(None, 50)

score_font = pygame.font.SysFont(None, 35)

def our_snake(snake_block, snake_list):

for x in snake_list:

pygame.draw.rect(dis, black, [x[0], x[1], snake_block, snake_block])

def message(msg, color):

mesg = font_style.render(msg, True, color)

dis.blit(mesg, [dis_width / 6, dis_height / 3])

def gameLoop(): creating a function

game_over = False

game_close = False

x1 = dis_width / 2

y1 = dis_height / 2

x1_change = 0

y1_change = 0

snake_List = []

Length_of_snake = 1

foodx = round(random.randrange(0, dis_width snake_block) / 10.0) * 10.0

foody = round(random.randrange(0, dis_height snake_block) / 10.0) * 10.0

while not game_over:

while game_close == True:

dis.fill(blue)

message("You Lost! Press QQuit or CPlay Again", red)

pygame.display.update()

for event in pygame.event.get():

if event.type == pygame.KEYDOWN:

if event.key == pygame.K_q:

game_over = True

game_close = False

if event.key == pygame.K_c:

gameLoop()

for event in pygame.event.get():

if event.type == pygame.QUIT:

game_over = True

if event.type == pygame.KEYDOWN:

if event.key == pygame.K_LEFT:

x1_change = snake_block

y1_change = 0

elif event.key == pygame.K_RIGHT:

x1_change = snake_block

y1_change = 0

elif event.key == pygame.K_UP:

y1_change = snake_block

x1_change = 0

elif event.key == pygame.K_DOWN:

y1_change = snake_block

x1_change = 0

if x1 >= dis_width or x1 < 0 or y1 >= dis_height or y1 < 0:

game_close = True

x1 = x1_change

y1 = y1_change

dis.fill(blue)

pygame.draw.rect(dis, green, [foodx, foody, snake_block, snake_block])

snake_Head = []

snake_Head.append(x1)

snake_Head.append(y1)

snake_List.append(snake_Head)

if len(snake_List) > Length_of_snake:

del snake_List[0]

for x in snake_List[:1]:

if x == snake_Head:

game_close = True

our_snake(snake_block, snake_List)

pygame.display.update()

if x1 == foodx and y1 == foody:

foodx = round(random.randrange(0, dis_width snake_block) / 10.0) * 10.0

foody = round(random.randrange(0, dis_height snake_block) / 10.0) * 10.0

Length_of_snake = 1

clock.tick(snake_speed)

pygame.quit()

quit()

gameLoop()

```

游戏玩法说明：

在这个简单版本的贪吃蛇游戏中，玩家需要控制蛇的移动，使其吃到屏幕上随机出现的食物。每吃到一个食物，蛇的长度就会增加，同时游戏速度也会略微加快。玩家需要注意避免让蛇撞到墙壁或者自己的身体，否则游戏就会结束。

玩家可以使用键盘上的上、下、左、右键来控制蛇的移动方向。当蛇头与食物重合时，即可实现吃到食物的目标。

以上是一个简单版的贪吃蛇游戏编程示例和玩法说明，希望对你有所帮助。